TMUA 2023 Paper 2 Q2 — Worked Solution

P2·Integration·4.5Official · 2023 · Q2

difference-of-squaresdefinite-integral

Evaluate

\int_{9}^{16} (\frac{1}{x} + x)^{2} d x - \int_{9}^{16} (\frac{1}{x} - x)^{2} d x .

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